1x^2=+8.5x-4

Solution for 1x^2=+8.5x-4 equation:

1x^2=+8.5x-4

We move all terms to the left:

1x^2-(+8.5x-4)=0

We add all the numbers together, and all the variables

1x^2-(8.5x-4)=0

We add all the numbers together, and all the variables

x^2-(8.5x-4)=0

We get rid of parentheses

x^2-8.5x+4=0

a = 1; b = -8.5; c = +4;
Δ = b2-4ac
Δ = -8.52-4·1·4
Δ = 56.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.5)-\sqrt{56.25}}{2*1}=\frac{8.5-\sqrt{56.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.5)+\sqrt{56.25}}{2*1}=\frac{8.5+\sqrt{56.25}}{2}
$